[Hamed]

Thanks about this code it works well but it has one problem when I use ' or " in my conditions I will get

Code:

Warning: Unexpected character in input: ''' (ASCII=39) state=1 in C:\xampp\htdocs\Rose\inc\template.class.php(34) : regexp code on line 1

is there any way to slove it or no I can not use ' or "
and one more thing when I use two vars in condition, condetion become ture although it is false.

PHP Code:

$code = preg_replace("~\{if ([^\}]+)\}(.*?)((:?\{else\})(.*?))?\{/if\}~sie", '($1 ? "$2" : ("$5" ? "$5" : null))', $code);