06-21-09, 01:58 PM
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Level II Curmudgeon
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Join Date: Dec 2004
Posts: 3,029
Thanks: 14
Thanked 34 Times in 33 Posts
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Quote:
Originally Posted by Nico
A variable name should follow after the arrow. And since variable names cannot begin with numbers, you're getting a parse error. Are you sure it's not something like this?
PHP Code:
$port = $data->port;
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Or possibly:
PHP Code:
$port = $data->'80';
[/QUOTE]
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