[=OTS=G-Man]

Originally Posted by End User

Or possibly:

PHP Code:

$port = $data->'80'; 

[/QUOTE]

well doing that is, well pointless.

cause if your using a static number then you might as well just do

$port = 80;

but because he is getting the data from a object then you would need

$port = $data->port;

or what ever the name of the variable for where the port is stored in is called.