[Rapid Dr3am]

I'm trying to run this command but getting an error:

%windir%\Microsoft.NET\Framework\v2.0.50727\aspnet _compiler -p E:\_development\in progress\ProjectWebsite -v / E:\_development\in progress\ProjectWebsite\precompiled

I'm getting told the path "E:\_development\in" does not exist. I'm pulling my hair out here, I even tried the old 8dot3 file names but nothing. I can't simply rename in progress to in-progress or anything, I have a lot of network shares that rely on that path.

Any help would be appreciated.

[digioz]

Try this instead:

Code:

%windir%\Microsoft.NET\Framework\v2.0.50727\aspnet _compiler -p "E:\_development\in progress\ProjectWebsite" -v / "E:\_development\in progress\ProjectWebsite\precompiled"

Its because of the space character you have in the above path on your E drive:

Rules for Command-Line Syntax

• Arguments are delimited by white space, which is either a space or a tab.
• The caret character (^) is not recognized as an escape character or delimiter. The character is handled completely by the command-line parser in the operating system before being passed to the argv array in the program.
• A string surrounded by double quotation marks ("string") is interpreted as a single argument, regardless of white space contained within. A quoted string can be embedded in an argument.
• A double quotation mark preceded by a backslash (\") is interpreted as a literal double quotation mark character (").
• Backslashes are interpreted literally, unless they immediately precede a double quotation mark.
• If an even number of backslashes is followed by a double quotation mark, one backslash is placed in the argv array for every pair of backslashes, and the double quotation mark is interpreted as a string delimiter.
• If an odd number of backslashes is followed by a double quotation mark, one backslash is placed in the argv array for every pair of backslashes, and the double quotation mark is "escaped" by the remaining backslash, causing a literal double quotation mark (") to be placed in argv.