[necro_mancer]

im kindly new here, and i have this kind of problem to create the programming. here is the problem:

Many people find it difficult to memorize phone numbers, so they use the correspondence between digits and letters to develop eight-letter (i want to use 8 letters and 8 numbers) words that correspond to their phone numbers.

For example, a person whose telephone number is 4263-7663 might use the correspondence to develop the eight-letter word “HANDSOME” so that people can easily remember his phone number. Each eight-letter word corresponds to exactly one eight-digit telephone number. A delivery service could surely do so with the number 3354-8379 stands for “DELIVERY”.

Each eight-digit phone number corresponds to many separate eight-letter words. Here is other example:

46774825 - HOSPITAL
26397467 - BODYSHOP
73743368 - RESIDENT
24276464 - CHARMING
42637663 - HANDSOME

here is the table on how i get the number generate into word:

2 = ABC
3 = DEF
4 = GHI
5 = JKL
6 = MNO
7 = PRS
8 = TUV
9 = WXY

Notes:
- the program can be key in the word then the output is a number or key in the number and the output is words.
- the words must be 8 character and contains 8 number only(see example)
- for your info, the character is not include Q and Z. And the number not include 0 and 1
- if there any question, please tell me..i need it before friday..please

[NeverMind]

to make this program function correctly and produce words that are meaningful is almost impossible AFAIK..
it's not that C/C++ can't do it! it's the logic behind it that lacks..
think of a program that could tell if the produced word makes sense or not!
your example 42637663 - HANDSOME might be produced as: IAODSMN which still represents the number!
to make the computer produce some meaningful words requires the program to have millions of words to check against, a dicitionary to be precise.
so imagine the program producing the word IAODSMN and then checking it against the dictionary and then when it doesn't find a match , changes a letter and re-check!
and the possibilties that can be found from an 8 chars word each slot (char) may have one of 3 chars is ALOT ... really ALOT.. I can't remember the formula to find the number of posibilties but I know it's not a small number at all

this is rather an interesting problem! so allow me to move this topic to "The Lounge" where it might get more attention..

if anyone has anything else to add, please do!

[LordDaimos]

Sounds a lot like the T9 system that many mobile phones use: http://www.t9.com/

[necro_mancer]

hye...i already go to www.t9.com and i got the idea...

after i read the question over and over...i realize...the question just wanna convert from word to number...

so i make it...but still have a problem... try find out yourself..
i found that...after the 8 phone number..there is a symbol..i dont know how to remove it....

BTW i use c not c++..

ONE MORE THING, DONT USE CAPITAL WORDS BECAUSE THE COMPUTER WILL HANG.. i dont know why...can somebody help me fix this problem?

thanks


/////////////////////////SOURCE CODE////////////////////////////////////////////

#include<stdio.h>
#include<conio.h>
#include<iomanip>
const char to_num_table[] = "2223334445556667077888999";
int main(void)
{


printf("\n**************************************** **************************************");
printf("\n**************************************** **************************************");
printf("\n DE TELEPHONE NUMBER WORDZ GENERATORZ v1.0");
printf("\n**************************************** **************************************");
printf("\n**************************************** **************************************\n\n\n");



int i,j;
char input[8];
char output[1];
char current_char;
printf("Enter The Name (Must be in 8 characters): \n\n\n");
for(i=0;i<8;i++)
{

scanf("%c",&input[i]);
}
printf("The Telephone Number Are:");
for (i=0; (current_char = input[i]) != 0;i++)

{

if (current_char >= 'A' && current_char <= 'Z')
output[i] = current_char - 'A';
else if (current_char >= 'a' && current_char <= 'z')
output[i] = to_num_table[current_char - 'a'];
else output[i] = current_char;

}

output[i] = 0;

puts(output);

getchar();
system ("pause");
return (0);

}

[NeverMind]

so you found yourself a solution!? that's nice
unfortunatly, my box doesn't have a C compiler so I can not test it but I will take the code to my other PC and try it

anyway, back to the C forum since you managed to create the app.