[jonnekke]

Hi there...

what is wrong about this AS? The only way to make it work is to change sendAndLoad to send. .But then a new broswer is opened. That's not what I want..!

emaileen = "mymail@mysite.com";
lvOutt = new LoadVars();
lvInn = new LoadVars();
            
lvOutt.email = emaileen; 
lvOutt.format = "h";
lvOutt.sendAndLoad("http://www.url.com/news/sendform.php?formnr=6", lvInn, "POST"); 

this line of code is in the same script (a bit above the fault part) and is working fine:

lvOut = new LoadVars();
lvIn = new LoadVars();
        
lvOut.action = "geefReactie"; 
lvOut.email = txt.text;
emaileen = lvOut.email;
lvOut.nrone = dataone;
lvOut.nrtwo = datatwo;      
 
lvOut.sendAndLoad("check.php", lvIn, "POST"); 

the only difference that I see is:
the url is on another domain in the "fault part" but this shouldn't be a problem is it?..

_j

[jonnekke]

another wierd thing:

as a test it local from my computer it works fine.. as soon as I
put it on my website it doesn't work..

_j

[UnrealEd]

the reason why it might not be working is because of a security setting of flash itself. When connecting to a remote host (ip) through the flash application, you need to approve that connection first.

Go to this url:
http://www.macromedia.com/support/do...manager04.html
And select "Add location..." from the "Edit locations" dropdown. Now add that reffers to your swf on your server, and hit "confirm". Refresh your flash application and test it again

Also: are you using the lvInn variable? If not, simply remove it as it is obsolete. You can pass on 2 parameters into the sendAndLoad method (the url, and the method), and it will still work

Just a note: it is best to declare the type of the variable as well. This is done by adding a colon after the name of the variable and then the name of the type. So a LoadVars object declaration should look like this:

var lvOut:LoadVars = new LoadVars(); 

I'm not sure if this has any advantage, but is defenitely nice when you start creating classes in which you need to declare the fields before you can assign a value to them

[jonnekke]

okay.. it took a looK at the URL.

is this "security" setting is client side.. ? if it is, is there a way to work arround this?.
so that everybody can use swf on my website?..

[UnrealEd]

This is indeed a client-side setting. So all visitors will need to approve the application.

I don't know if there's a workaround via flash, but I sure know there's a workaround using php. Instead of submitting the form to http://www.url.com/news/sendform.php?formnr=6, submit it to a page on your server (which is localhost for the flash application), and then submit the form, using php, to http://www.url.com/news/sendform.php?formnr=6. Grab the results, and send them back to flash. It's very easy, since you allready have the mechanism up and running. You just need to create a new page that will send the request to the correct page.

[jonnekke]

okay.. I'll give this a try... do you know how to
submit a form automaticly..
because actually I don't want an extra page to be seen.

So the data should be submitted but the page not changed...

you got what I mean?.

_j

[UnrealEd]

yup. It's actually pretty easy. You can either use cURL, or create a socket connection to the http://www.url.com/news/sendform.php?formnr=6 script.

Here's an example on how to do it with cURL:

PHP Code:

$curl = curl_init ("http://www.url.com/news/sendform.php?formnr=6");
curl_setopt ($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt ($curl, CURLOPT_POST, true);
curl_setopt ($curl, CURLOPT_POSTFIELDS, sprintf ("email=%s&format=%s", urlencode ($_POST['email']), strval ($_POST['format']));

$results = curl_exec ();
curl_close ($curl); 

a socket example:

PHP Code:

$fp = @fsockopen ("www.url.com", 80, $errNo, $errStr, 15); // never add the http:// protocol in front of the url
if (!$fp) {
  die ("An error occured: ($errNo) $errStr");
} else {
  $request = "POST news/sendform?formnr=6 HTTP/1.1\r\n";
  $request .= "Host: " . $_SERVER['HTTP_HOST'] . "\r\n";
  $request .= "User-Agent: " . $_SERVER['HTTP_USER_AGENT'] . "\r\n";
  $request .= "Content-Type: application/x-www-form-urlencoded\r\n";
  $request .= "Content-Legnth: " . strlen (sprintf ('email=%s&format=%s', urlencode ($_POST['email']), strval ($_POST['format']))) . "\r\n";
  $request .= "Connection:close\r\n\r\n";
  if (!@frwite ($fp, $request)) {
    die ("An error occured");
  } else {
    $returned = NULL;
    while (($returned .= fgets ($fp)) !== false);
    // $returned will hold the returned data from the website.
  }
} 

[jonnekke]

shouldn't there be .php in this line?

PHP Code:

$request = "POST news/sendform?formnr=6 HTTP/1.1\r\n"; 

sot that is goes:

PHP Code:

$request = "POST news/sendform.php?formnr=6 HTTP/1.1\r\n"; 

[UnrealEd]

Oops, my mistake

Also: you should replace "Content-Legnth" by "Content-Length", another typo

[jonnekke]

this past cause an error:

PHP Code:

if (!$filePointer) 
{
throw new Exception("Chyba spojeni $errorNumber $errorString");
} 

if I delete this part the page is loaded good. What does this part do and what can be the error?..