Collecting a value from a form

DJ Steffo · #1 (**permalink**) 11-13-04, 09:44 AM

Hi!
I have a fairly advance PHP page with a script that uses the value 'a' to match with values in an array. The easy problem is that:....

The 'a' has been given so far but now I would like the webuser to input the value 'a' when he is visiting the PHP page.

What should the FORM look like to send the value to the script?
How do I set the value a=100 as the default value in the form?

I have seen examples where info is sent to a new PHP page but I am already standing in mine. Maybe it causes a conflict?

Code:

<form method=???? action="????">
What is your desired value? 
<input type=integer name="value" size=6 maxlength=6>
<input type="submit" value="SUBMIT!">
</form>

Thank you for your time.

Y3000 · #2 (**permalink**) 11-13-04, 09:57 AM

If I understood correctly the variable you are trying to send is called a!

Code:

<form action="script.php" method="POST">
<input type="text" name="a" value="100" size="6" maxlength="6">
<input type="submit" value="Submit">
</form>

Where script.php is the name of your script file.

...however...

If you are within PHP <? ?> you will need to echo this... and remove the "s eg.

Code:

echo "<form action=script.php method=POST>
<input type=text name=a value=100 size=6 maxlength=6>
<input type=submit value=Submit>
</form>";

...however...

You will probably only want to show the form if a has not been set...

Put this at the top of the script within <? and ?>

Code:

if (!$a) {
echo "<form action=script.php method=POST>
<input type=text name=a value=100 size=6 maxlength=6>
<input type=submit value=Submit>
</form>";
exit;
}

The exit; will stop the rest of the script from running, remove this if this is not what you want. Like this they will need to complete the form before the script will run!

Hope that helps.

DJ Steffo · #3 (**permalink**) 11-13-04, 02:46 PM

Thanks for the examples it made me come closer to my goal. Unfortunately there are conflicts.

I have today the following code on the page: "script.php"

Code:

<?php
...
$a=30;
$sql = "SELECT	*,
CASE 
	WHEN ".$a." > ......

'a' must have a starting value for the page to be able to display the table. Therefor it has above been given 30.

I believe this is why nothing happens when I follow your recommendation

Code:

<form action=script.php method=POST>
<input type=text name=a value=100 size=6 maxlength=6>
<input type=submit value=Submit>
</form>

Which I have written in the body of "script.php".
Since all javascripts and fetching is done in the <head> and my <form>
is written further down in the <body> it creates a conflict?

I would like the table to be displayed from the start with a given value for 'a'.
Then the user could use the form to show a new table for their chosen value.

Y3000 · #4 (**permalink**) 11-14-04, 05:34 AM

Hiya,

Okay - The form is setting the variable a.
But... the line $a=30; is then resetting the variable to 30 regardless of what the user submitted.

Put the following at the top of your page and remove the old line $a=30;

PHP Code:


			
<?PHP

if (!$a) { $a=30; }

echo "<form action=$PHP_SELF method=POST>

<input type=text name=a value=100 size=6 maxlength=6>

<input type=submit value=Submit>

</form>";

?>