[endrigecko]

hi, i'm a newbie here..i just installed PHP 4.3.10 in my computer...i want to use imagecreate() function and i have a slight problem with it...everytime i try to run this script (which is the example from php.net):

<?
header("Content-type: image/png");
$im = @imagecreate(100, 50)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 255, 255, 255);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>

the browser said "The Image "http://localhost/belajar/imagetest.php" cannot be displayed, because it contains errors"
I hope somebody can help me with this...thx

[Sabu]

You should comment out the header and the imagepng line to see if it's outputting any errors.

[thanh_bkhn]

Be sure the gd2 extensions is installed first.

in the php.ini file, put the following line:
extension=php_gd2.dll

[endrigecko]

i just put the line extension=php_gd2.dll in the php.ini file nad new problem occur..it seems a window pops tells a warning:

Unknown(): gd: Unable to initializa module
Module compiled with module API=20010901, debug=0, thread safety=1
PHP compiled with module API=20020429, debug=0, thread-safety=1
These options need to match

i'm using a php triad 2.2.1 and i just upgrade the PHP in the directory from version 4.1.1 to 4.3.1 is that could be the problem? thanks for the reply..