[Baho]

i wanna change the picture in my page, using another one form a database
so i tried 2 pass the variable $row[11] (which is the path of the pic)
into a javascript function but it didnt work.

<? echo "<script language=javascript>";
echo "function pic(p) {";
echo "document.images [\"picture\"].src = p";
echo "}";
echo "</script>";?>


<? echo "<a href=# onclick=\"pic(".$row[11].");\">";?>Picture</a>

<img src="<? echo $row[10];?>" height="100%" width="100%" border="0" name="picture">

[kjmatthews]

That is some ugly lookin' code. I am by no means a Javascript man, but try this. Write out the Javascript function (complete with PHP variables) and resultant HTML as though it were not being echoed by PHP, complete with line breaks, indentation, and without escaping double quotes, etc. I think it would look something like this:

Code:

<script language="javascript">
 function pic(p) {
   document.images[picture].src = p
 }
</script>

<a href="#" onclick="pic($row[11])">Picture</a>

<img src="$row[10]" height="100%" width="100%" border="0" name="picture">

Then we can use the extremely useful HEREDOC syntax in PHP to echo this all as typed and with variable substitution without having to escape all those pesky quotes and whatnot, viz:

PHP Code:

<?php

echo<<<END

<script language="javascript">

 function pic(p) {

   document.images [picture].src = p

 }

</script>



<a href="#" onclick="pic($row[11])">Picture</a>



<img src="$row[10]" height="100%" width="100%" border="0" name="picture">

END;

If it still doesn't work, you know it is the Javascript function that is the problem and not the PHP.

[FiRe]

PHP Code:

<? echo '<a href="#" onclick="pic('.$row[11].');">Picture</a>'; ?>