[dayzeday]

I am trying to get an image field to NOT display if a image is NOT present. I managed to get this to work displaying the path but I can not get it to work with the image. It gives me a string error. I have tried it a few ways and same problem. Please HELP!

Here is the path one I used:

PHP Code:

 <?php if ($row_Recordset1['photo'] == null) echo ""; ?>

Here is the image one I used:

PHP Code:

 <?php if ($row_Recordset1['photo'] == not null) echo "<img src='../IMAGES/BK-1.gif'/>"; ?>

[NeverMind]

you can't use not in php
you will have to use != instead..

PHP Code:

if ($row_Recordset1['photo'] !== null)

   echo "<img src='../IMAGES/BK-1.gif'/>"; 

but this will display this BK-1.gif if this $row_Recordset1['photo'] does exist!