[ascanio]

Ok here it is the upload function that i have on my website, I would like to integrate a resize function on the upload function
so what i want to do is replae this message ... can any body help me?

PHP Code:

$upfile_name[$x]." exceeds the maximum image size limit.<br> 

for a resize function
so if the image size is bigger than the maximage then the image is resize

PHP Code:

// UPLOAD FUNCTION

if ($email && $password && $upimages){

    $validlogin = verifylogin($email,$password);

    if (!$validlogin){

        $pagetitle = $ihtitle.": Invalid Email and/or Password";

        if ($headerfile) include $headerfile;

        print "The email or password you've entered is incorrect. Please go back and try again.";

        if ($footerfile) include $footerfile;

        exit;

    }

    if (count($upfile)==0) $uploadstatus = "You haven't selected any files to upload.<br>";



    if (!$status && !$uploadstatus){

        for($x=0;$x<count($upfile);$x++){

            if ($upfile_name[$x]){

                $upfilestatus = "";

                if (($maximgsize!="") && ($upfile_size[$x]>$maximgsize)) $upfilestatus = $upfile_name[$x]." exceeds the maximum image size limit.<br>";

                if (($maximagesperaccount!="") && (numimagesacct($validlogin)>=$maximagesperaccount)) $upfilestatus = $upfile_name[$x]." - You have uploaded the maximum number of images in your account.<br>";

                $imgtyp = substr($upfile_name[$x], -3);

                $imgtyp = strtolower($imgtyp);

                if (($imgtyp!="jpg") && ($imgtyp!="gif") && ($imgtyp!="png")) $upfilestatus = $upfile_name[$x]." is not a valid image (JPG, GIF and PNG only).<br>";

                $sql = "select filename from $tablepics where owner='$validlogin' and filename='$upfile_name[$x]'";

                $result = mysql_query($sql) or die("Failed: $sql");

                $numrows = mysql_num_rows($result);

                if ($numrows!=0) $upfilestatus = $upfile_name[$x]." - File already exists.<br>";

                if (!$upfilestatus){

                    $sql = "insert into $tablepics values('', '$validlogin', '$upfile_name[$x]', '$upfile_size[$x]', '0', now())"; 

                    $result = mysql_query($sql) or die("Failed: $sql");

                    @copy($upfile[$x], $upfilesfolder.$validlogin."-".$upfile_name[$x]);

                    $uppedfiles = $upfile_name[$x]." successfully uploaded.<br>";

                }

                $uploadstatus .= $upfilestatus;

            }

        }

    }

} 

thanks in advance