[zoliky]

I have the following php code

PHP Code:

date('d-m-Y') 

This code show the current date in day-month-year format.
What I need to do to add +1 month to current date ?

I want to show a line with current date and another line with current date + 1 month.

An example:

- 31-10-2006
- 31-11-2006

Thanks !

[Nico]

PHP Code:

 date('d-m-Y', strtotime('+1 Month')); 

[zoliky]

I have two text input field. Each input field hold a date. By default the first field hold every time the current date, and second field hold te current date + 1 month.

Code:

Date1  <input type="text" value="31-10-2006" name="textfield" />
Date2  <input type="text" value="31-11-2006" name="textfield" />

If someone change the dates on page (if default value is not good), I need to check if second date is not bigger than +2 months..

I need to check this thing after form submited. Any idea how to do this?
Thanks

[odi]

this could help you, it's not that clean, because it defines a month as 31 days, but maybe that's enough for you:

PHP Code:

function diff_in_range($date1,$date2,$range=1,$seperator="-") {

    //split parts of the date. IMPORTANT: dd mm yyyy order (seperator is an argument)

    $date1 = explode($seperator,$date1);

    $date2 = explode($seperator,$date2);

    

    //create UNIX-Time (seconds since the epoche)

    $unix_date1 = mktime(0,0,0,$date1[1],$date1[0],$date1[2]);

    $unix_date2 = mktime(0,0,0,$date2[1],$date2[0],$date2[2]);

    

    //caluclate the diff

    $unix_diff = 0;

    if ($unix_date1 > $unix_date2) {

        $unix_diff = $unix_date1 - $unix_date2;

    } else {

        $unix_diff = $unix_date2 - $unix_date1;

    }

    

    //If it's not too important, let's define a month as 31 days (60*60*24*31 = 2595600), this is not always true (e.g. february)

    if ($unix_diff < (2595600*$range)) {

        return true;

    } else {

        return false;

    }

}

$date1 = "31-11-2006";

$date2 = "30-12-2006";



//check if there are more than 2 month (i.e. 62 days) between the dates

$result = diff_in_range($date1,$date2,2); 

[zoliky]

For me is enough if PHP check the interval between date1 and date 2 if not bigger than 60 days.

[zoliky]

I receive two date in following format

PHP Code:

$_POST['pubdate'] // day-month-year   (02-11-2006)

$_POST['expdate'] // day-month-year   (01-01-2007) 

I need to get the difference between two date in days. Now I need to get 60 days.

When i put this :

PHP Code:

$_POST['pubdate'] // day-month-year   (02-11-2006)

$_POST['expdate'] // day-month-year   (02-12-2006) 

I need to get only 30 days.

I try to convert my date to unixtime format and use unixToJD function but no luck.. Anyone help me a bit ? I need to solve this problem today.

Thanks !

[odi]

I don't understand this 30-60 days issue, but to get the difference in days between two dates, you can use a modified version of my function above:

PHP Code:

function diff_days($date1,$date2,$seperator="-") {

    //split parts of the date. IMPORTANT: dd mm yyyy order (seperator is an argument)

    $date1 = explode($seperator,$date1);

    $date2 = explode($seperator,$date2);

    

    //create UNIX-Time (seconds since the epoche)

    $unix_date1 = mktime(0,0,0,$date1[1],$date1[0],$date1[2]);

    $unix_date2 = mktime(0,0,0,$date2[1],$date2[0],$date2[2]);

    

    //caluclate the diff

    $unix_diff = 0;

    if ($unix_date1 > $unix_date2) {

        $unix_diff = $unix_date1 - $unix_date2;

    } else {

        $unix_diff = $unix_date2 - $unix_date1;

    }

    //one day has 86400 seconds

    return $unix_diff / 86400;

}

$date1 = "29-11-2006";

$date2 = "01-12-2006";



//this prints "2"

echo diff_days($date1,$date2); 

with the result of this function you can check if the value is >30 or <60 or whatever you want.

[zoliky]

If date2 is smaller than date1 I need to show an error. Your function know to do this ?
I want to use this feature to publish an article, and user need to specify the start date (date1) when article appear and end date (date2) when article expire.

Thanks

[zoliky]

I have the following date :

02-11-2006

in $pubdate variable.
What I need to do to convert this date to english format : 2006-11-02 ?

[Nico]

Try this

PHP Code:

$pubdate = '02-11-2006';



$newdate = implode('-', array_reverse(explode('-', $pubdate)));