[Oskare100]

Hello,
When the scripts requests from the Ebay API it need to supply the current time and date plus five days and minus five days.

It needs to be in this format: 2007-01-17T18:28:52.799Z
So if now is 2007-01-20 18:28:52 then I need he script to create two variables with the following values;
(Minus five days) $time_from = 2007-01-15T18:28:52.799Z
(Plus five days) $time_to: = 2007-01-25T18:28:52.799Z

How can I make PHP add minus five days to, for example, $time_from and plus five days to, for example, $time_to as above?

Thanks in advance,
/Oskar R

[grafman]

This is clearly illustrated in the date function in the php manual.

PHP Code:

<?php

$x = date('d');

echo $x . '<br>';

$y = date('d') + 5;

echo $y . '<br>';

$z = date('d') - 5;

echo $z;

?>

All you have to do is use the format specifiers to get the output format you want then add and subtract from it just like you would any normal math expression.

[job0107]

This should do what you want.

PHP Code:

<?php

$date_to_calculate = "2007-01-20 18:28:52.799";

$year = substr($date_to_calculate, 0, 4);

$year1 = $year2 = $year;

$month = substr($date_to_calculate, 5, 2);

$month1 = $month2 = $month;

$day_minus = $day_plus = substr($date_to_calculate, 8, 2);

$day_minus -= 5;

$day_plus += 5;

$remainder = substr($date_to_calculate, 11, 12);

$days_in_month = date(t, mktime(0, 0, 0, $month, 0, $year));

if($day_minus < 1)

{

 $month1--;

 If($month1 < 1){$month1 += 12;$year1--;$offset = 1;}else{$offset = -1;}

 $days_in_month1 = date(t, mktime(0, 0, 0, $month1, 0, $year1));

 $day_minus +=  $days_in_month1 + $offset;

 }

If($day_plus > $days_in_month)

{

 $month2++;

 if($month2 > 12){$month2 -= 12;$year2++;}

 $days_in_month2 = date(t, mktime(0, 0, 0, $month2, 0, $year2));

 $day_plus -= $days_in_month2;

 }

if(strlen($month1) < 2){$month1 = "0".$month1;}

if(strlen($day_minus) < 2){$day_minus = "0".$day_minus;}

if(strlen($month2) < 2){$month2 = "0".$month2;}

if(strlen($day_plus) < 2){$day_plus = "0".$day_plus;}

$time_from = ($year1."-".$month1."-".$day_minus."T".$remainder."Z");

$time_to = ($year2."-".$month2."-".$day_plus."T".$remainder."Z");

echo($time_from."<br>".$time_to);

?>

[Nico]

A lot of code for something like that. Give this a try:

PHP Code:

$date = '2007-01-17T18:28:52.799Z';



$timestamp = strtotime($date);



$time_from = date('Y-m-d\TH:i:s.799\Z', $timestamp - 3600 * 24 * 5);

$time_to   = date('Y-m-d\TH:i:s.799\Z', $timestamp + 3600 * 24 * 5); 

[yonta]

How about something like this

PHP Code:

$plus5 = date("Y-m-d", mktime(date('h'), date('i'), date('s'), date('m'), date('d')+5, date("Y")));



$minus5 = date("Y-m-d", mktime(date('h'), date('i'), date('s'), date('m'), date('d')-5, date("Y"))); 

Just put in the correct format you need (replace "Y-m-d" ) and it should do the trick.

Good luck