[miniature]

Title.......^
This is the code:

calendar.php: (the calendar..)

PHP Code:

$time = time();

 

$today = getdate($time);

$mday = $today['mday'];

$mon = $today['mon'];   

$year = $today['year'];

echo "<a href='javascript:;' onclick='javascript:ajax_calendar();'>שנה קודמת</a>\n"; 

A JS code with the AJAX:

HTML Code:

function ajax_support() {
  try {
    // Firefox, Opera 8.0+, Safari
    return new XMLHttpRequest();
  }
  catch(e) {
    // Internet Explorer
    try {
      return new ActiveXObject("Msxml2.XMLHTTP");
    }
    catch(e) {
      try {
        return new ActiveXObject("Microsoft.XMLHTTP");
      }
      catch(e) {
        alert("Your browser does not support AJAX!");
        return false;
      }
    }
  }
}
function ajax_calendar() {
  var ajax_cal = ajax_support();
  ajax_cal.onreadystatechange=function() {
    if((ajax_cal.readyState == 4) && (ajax_cal.status == 200)) {
      return ajax_cal.responseText;
    }
  }
  ajax_cal.open("GET","calendar_ajax.php",true);
  ajax_cal.send(null);
}

calendar_ajax.php:

PHP Code:

<?php

  $time_ajax = time();

 

  $today_ajax = getdate($time_ajax);

  $mday_ajax = $today_ajax['mday'];

  $mon_ajax = $today_ajax['mon'];   

  $year_ajax = $today_ajax['year'];  

  $time = mktime(0, 0, 0, $mon_ajax,$mday_ajax,$year_ajax-1);

?>

It's not working and nothing is happen.
I want it define in calendar.php the variable $time like it returned from calendar_ajax.php .
Moreover, I am searching for a way that I would transfer information from calendar.php to calendar_ajax.php so that it will be the real date that transfered and not a time() .

I'm sure there is a lot of mistakes in the code because it's the first time that I am trying to use AJAX.


Thank you,

[job0107]

I really don't understand what you are trying to do.

Can you please try to explain it a little better?