[tricks22]

Ok heres my code snippet.

PHP Code:

$myfile = "images.php";
            $fh = fopen($myfile, 'w') or die("can't open file");
            
            
            $images = "<?php \n ";
            
            //Runs a loop that sets $images to be a huge long string containing alot of image info for up to 10 images
            for($i=1; $i <=$c; $i++)
            {
                $images .= "$img = array(); \n $img[\'filename\'] = \"" . $filename[$i] . "\";\n$img[\'displayname\'] = \"" . $displayname[$i] . "\"; \n $images[] = $img; \n";
            }
            
            $images .="?>";
            
            
            //Writes to images.php
            fwrite($fh, $images);

and im getting this error: T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING


on line 71, which is this line : }

the line before it is probably the problem, its:

PHP Code:

$images .= "$img = array(); \n $img[\'filename\'] = \"" . $filename[$i] . "\";\n$img[\'displayname\'] = \"" . $displayname[$i] . "\"; \n $images[] = $img; \n"; 

The purpose of the script is to write:

PHP Code:

<?php
$img = array();
$img['filename'] = "a";
            $img['displayname'] = "a";
            $images[] = $img;
?>

Into images.php. Can anyone figure out where the error is coming from?

Thanks in advance, really appreciate the help.

[wirehopper]

Instead of writing out the information in an array, you could use a CSV (comma separated values) file - like so:

filename1,displayname1
filename2,displayname2

You can read the file with fgetcsv and write it with fputcsv.

http://us2.php.net/manual/en/function.fgetcsv.php
http://us2.php.net/manual/en/function.fputcsv.php

This is also potentially more secure, as the generated file is not executeable.

[tricks22]

I appreciate the advise, but I'm doing work for somebody else, and they want it in a particular format (using arrays). Also security is not an issue.

[wirehopper]

PHP Code:

$images .= "$img = array(); \n $img[\'filename\'] = \"" . $filename[$i] . "\";\n$img[\'displayname\'] = \"" . $displayname[$i] . "\"; \n $images[] = $img; \n"; 

should be able to be rewritten as:

PHP Code:

$images .= "$img = array();\n$img['filename'] = '{$filename[$i]}';\n$img['displayname'] = '{$displayname[$i]}';\n$images[] = $img;\n"; 

... which should solve the parser error.

[tricks22]

That solves 1 problem. I shouldn't of escaped single quotes.

Also I should of escaped my $ signs that are in double quotes.

Thanks thou.