$_POST tried

reshma · #1 (**permalink**) 04-01-09, 10:56 PM

i did what u guys suggested,but still i am not anle to get it...this is the code,

<html>

<body>

<form name="myForm" >
Customer ID: <input type= "text" size=3 name="customer_id" onBlur=getInfo();><br>
<input type="submit" value= "Submit" name= "customerid">
</form>
<div id="txtHint"><b>Customer info will be listed here.</b></div>

</body>

</html>

and the PHP code is:

<?php
$customer_id=$_POST['customerid'];
if($customer_id == 003)
{
echo "Jim";
}

else {echo " No customer name available";}
?>

kaceykeleher · #2 (**permalink**) 04-01-09, 11:45 PM

What exactly are you attempting to do?

And for the future, be sure and put your code between the proper tags, which you can find in the posting box. For example, your PHP code should be placed between the PHP brackets, and the same with HTML. It makes it much easier to read.

Correct me if I'm wrong, but it looks like you are using the form to display a persons name once they enter their Customer ID, and once they click outside of the box, using JavaScript? It also looks as though you are not using a database to store information, but instead just telling your code that if they happen to enter 003 then the name 'Jim' will be displayed.

If you could let me know a little bit about what you are trying to do, I'd be more than happy to give you any help I can. Also, could you post your JavaScript for the getInfo() function?

reshma · #3 (**permalink**) 04-01-09, 11:50 PM

I am sorry if u had trouble reading the code. i basically just want to check if the value of customer id is getting posted to my PHP code from the HTML form, and thats the reason why i don't have a database mentioned.

I hope u understood what my point is.

Thank you

kaceykeleher · #4 (**permalink**) 04-02-09, 12:13 AM

Alright, I made a quick little HTML/PHP file without any storage database. Basically, it uses a form to check an ID, and if they enter a specific number, it calls back the name.

Here is the code:

PHP Code:


			
<?



if ( isset($_POST['submit']) )

{

    $customerID = $_POST['customerID'];

    $customerName = 'Jim';

    

    if ($customerID == "003")

    {

        $customerInfo = 'Hello, ' . $customerName . '.';

    }

    else

    {

        $customerInfo = 'We do not have any information for Customer ID # ' . $customerID . '';

    }

}



?>



<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

<title>Untitled Document</title>

</head>

<body>

<form action="" method="post">

<div id="container">

    <div class="formRow">

        Customer ID:

        <input name="customerID" type="text" size="20" />

    </div>

    <div class="formRow">

        <input name="submit" type="submit" value="submit" />

    </div>

    <div class="formRow">

        <? echo $customerInfo; ?>

    </div>

</div>

</form>

</body>

</html>

If you would like to see it in action, go to this page. Customer # 003 has information stored, but others do not.

Is this what you are interested in?

reshma · #5 (**permalink**) 04-02-09, 12:17 AM

Thank you so much. This exactly what i was trying to do, i hope i can get back to you in future if have any more doubts.The thing is i am completely new to this.Thanks again

kaceykeleher · #6 (**permalink**) 04-02-09, 12:26 AM

Not a problem! And just so you know, if you'd like to add more information to a specific ID, make sure you add the variables under $customerID before calling them anywhere else.

An example:

PHP Code:


			
if ( isset($_POST['submit']) )
{
    $customerID = $_POST['customerID'];
    $customerName = 'Jim';
    $customerAddress = '123 Jones Street';
    $customerState = 'Iowa';
         
    if ($customerID == "003")
    {
        $customerInfo = 'Hello, ' . $customerName . '.<br />';
        $customerInfo .= 'Your address is: ' . $customerAddress . ' ' . $customerState . ''; //Be sure that any additional lines use $customerInfo .= 'info';
    }

Good luck!

mdhall · #7 (**permalink**) 04-04-09, 06:27 PM

I think the original issue in your script was that the form field name "customer_id" didn't match $_POST['customerid'];, so you would never get an accurate result.