Creating an image with php_gd2.dll

DimensionX · #1 (**permalink**) 06-13-09, 12:17 AM

Hi,

I'm currently learning how to draw using php_gd2.dll, I've made a file that when it's just php works fine, if I attach some other code that displays the results of a database and puts the in a table with php using echos the page comes up with an error, again the grab from a database and put it into a table code works fine also, I'm wondering if when you draw that it turns the page into a complete image which would mean if i want to include the image i would have to link it or include it on the page, is that correct?

PHP Code:


			
<html>
<head><title></title>
<?php
    require 'core/config.php';
        
       //Assign the query
    $query = "SELECT * FROM client ORDER BY clientId ASC";

    //Execute the query
    $result = mysql_query( $query );
    if(!$result){
        die ("Could not query the database: <br />". mysql_error());
    }
    
    function image($height,$width) {
        //Set up image
        $im = imagecreatetruecolor($width, $height);
        $white = imagecolorallocate ($im, 255, 255, 255);
        $blue = imagecolorallocate ($im, 0, 0, 64);
            
        //Draw image
        imagefill($im, 0, 0, $blue);
        imageline($im, 0, 0, $width, $height, $white);
        imagestring ($im, 4, 50, 150, 'Yay', $white);
        
        //Output file
        Header ('Content-type: image/png');
        imagepng ($im);
        
        //Clean up
        imagedestroy($im);
    }
?>
</head>
<body>
<?php
    $varWidth = 200;
    $varHeight = 200;
    image($varWidth,$varHeight);
    
        //Creating table
    echo '<table border="1">';
    echo "<tr><td>Client ID</td><td>First name</td><td>Surname</td><td>Address</td><td>Town</td><td>State</td><td>Zip code</td></tr>";

    while ($result_row = mysql_fetch_array($result, MYSQL_ASSOC)){
        echo "<tr><td>";        
        echo $result_row["clientId"] . '</td><td>';
        echo $result_row["firstName"] . '</td><td>';
        echo $result_row["surName"] . '</td><td>';
        echo $result_row["address"] . '</td><td>';
        echo $result_row["town"] . '</td><td>';
        echo $result_row["state"] . '</td><td>';
        echo $result_row["zip"] . '</td><td>';
    }

    echo ("</table>");
?>

</body>
</html>

sorry about the formatting I'm still new to php and haven't learned the coding conventions, the strange thing is if i take it out of the html shell the image drawing works perfectly :S

Any help or advice is appreciated,

thanks : )

DimensionX · #2 (**permalink**) 06-17-09, 05:10 PM

Maybe i should clarify the question a little?

ok when you make an image out of php does it treat the whole page as an image, what i mean is if your going to use a dynamically made image should you make it then include it on another page? cause as i mentioned above i've tried to draw an image and then include html commands but it came up with errors.

again, any help is appreciated

job0107 · #3 (**permalink**) 06-17-09, 09:31 PM

You need to create all the images you want first, and store them in files.
Then display them in image elements in the HTML.

Something like this:

PHP Code:


			
<?php
        $file_name = "img1.png";
        $text = "Success!!!";
        $im = imagecreatetruecolor(200, 200);
        $white = imagecolorallocate($im, 255, 255, 255);
        $blue = imagecolorallocate($im, 0, 0, 64);
        imagefill($im, 0, 0, $blue);
        imageline($im, 0, 0, $width, $height, $white);
        imagestring($im, 4, 50, 150, $text, $white);
        imagepng($im, $file_name);
        imagedestroy($im);
?>
<html>
<body>
<img src="img1.png" alt="img1.png">
<div>img1.png</div>
</body>
</html>

Nico · #4 (**permalink**) 06-18-09, 03:56 AM

Quote:

Originally Posted by job0107

You need to create all the images you want first, and store them in files.

Either that, or you could put the image stuff in an separate file, and embed this as image instead.

HTML Code:

<img src="image.php" />

Jcbones · #5 (**permalink**) 06-18-09, 03:14 PM

To answer your question explicitly, YES.

When you send this header

PHP Code:


			
Header ('Content-type: image/png');

The whole page is an image.

DimensionX · #6 (**permalink**) 06-19-09, 12:22 AM

thanks!!! sooooo much : D

been checking often lol, thanks alot for the replies : )

and yes that solves my question : )