[Mass Zero]

Hey,

I was doing a small file listing script and I wanted to exclude subdirectories from being shown. For that, I used:

PHP Code:

if(is_dir($file)) {

continue;

} 

This isn't working though. After checking with var_dump(is_dir($file));, it seems subdirectories aren't being recognized as directories, since it returned false.

Anyone know how I can fix this?

Thanks.

[Nico]

Can you post some more code? I'm guessing $file doesn't actually contain the expected value.

[Mass Zero]

PHP Code:

    $dir = 'random/dir/here';

    $result = array();

    if(is_dir($dir)) {

        if($opendir = opendir($dir) or die('Unable to open ' . $dir . '.')) {

            while($file = readdir($opendir)) {

                if(is_dir($file)) {

                    continue;

                }

                elseif($file != '.' && $file != '..') {

                    $result[] = $file;

                }

            }

            closedir($opendir);

            sort($result);

            for($loop = 0; isset($result[$loop]); $loop++) {

                echo $result[$loop] . '<br />';

            }

        }

    } 

[Nico]

While var_dump() is a nice debugging function, a simple "echo" would probably have led you to the solution.

PHP Code:

if (is_dir($dir . '/' . $file))

    continue; 

... although, I'd save the is_dir/continue/elseif part, by doing it this way:

PHP Code:

if (is_file($dir . '/' . $file))

    $result[] = $file; 

PHP Code:

<?php



$dir = 'random/dir/here';

$result = array();



if (is_dir($dir))

{

    if ($opendir = opendir($dir) or die('Unable to open ' . $dir . '.'))

    {

        while (($file = readdir($opendir)) !== false)

        {

            if (is_file($dir . '/' . $file))

                $result[] = $file;

        }

        

        closedir($opendir);

        sort($result);



        echo implode("<br />\n", $result);

    }

}  





?>