[braca86]

ok, this is the code im using for uploading files on server... all i want is to send email as notificaction that file is successful uploaded and with link for the file or the file name.... any help?

PHP Code:

<?php
//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","1000");

//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}

//This variable is used as a flag. The value is initialized with 0 (meaning no error found) and it will be changed to 1 if an errro occures. If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST['Submit']))
{
//reads the name of the file the user submitted for uploading
$image=$_FILES['image']['name'];
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES['image']['name']);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file, otherwize we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
//print error message
echo '<h1>Unknown extension!</h1>';
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file in which the uploaded file was stored on the server
$size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo '<h1>You have exceeded the size limit!</h1>';
$errors=1;
}


//the new name will be containing the full path where will be stored (images folder)
$newname="http://www.hotscripts.com/forums/images/uploads/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied)
{
echo '<h1>Copy unsuccessfull!</h1>';
$errors=1;
}}}}

//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
{
echo "<h1>File Uploaded Successfully! Try again!</h1>";
}

?>

<!--next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" -->
<form name="newad" method="post" enctype="multipart/form-data" action="">
<table>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input name="Submit" type="submit" value="Upload image"></td></tr>
</table>
</form>

[therocket954]

Try this.... Replace the bottom block of your PHP code with this: (Of course, you'll need to modify it with your correct email address and domain name.

PHP Code:

//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
{
    $to = "me@mydomain.com";
    $subject = "File upload";
    $body = "My file uploaded successfully... The link is: ";
    $body .= "http://mydomain.com/" .$newname;
    
    // Send the email
    mail($to, $subject, $body, "From: <me@mydomain.com>");
    
    // Show message
    echo "<h1>File Uploaded Successfully! Try again!</h1>";
} 

[braca86]

i did that and im getting error message

Warning: copy(images/uploads/) [function.copy]: failed to open stream: Is a directory in /home/antline/public_html/email.php on line 53

and line 53 is

$copied = copy($_FILES['image']['tmp_name'], $newname);

[Nico]

PHP Code:

$newname="http://www.hotscripts.com/forums/images/uploads/".$image_name; 

... should probably be:

PHP Code:

$newname="http://www.hotscripts.com/forums/images/uploads/".$image; 

Although, you should use move_uploaded_file instead of copy().

[braca86]

now working perfectly ok .....
just 1 more thing... i'w added inputbox for the customer to write his name

<input type="text" name="firstname" id="firstname" />

how to send that along with the rest data in email???

[therocket954]

This will work:

Change your top block of PHP to this:

PHP Code:

//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","1000");
// Get name from form
$firstname = $_POST['firstname']; 

And then in your block of code that sends the email change to this:

PHP Code:

//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
{
    $to = "me@mydomain.com";
    $subject = "File upload";
    $body = "My file uploaded successfully... The link is: " .$newname;
    $body .= "\n"; // just creates a new line
    $body .= "Name: " .$firstname;
    
    // Send the email
    mail($to, $subject, $body, "From: <me@mydomain.com>");
    
    // Show message
    echo "<h1>File Uploaded Successfully! Try again!</h1>";
} 

[braca86]

cool.... working... tnx all...

[ContentSpooling]

Thanks therocket for the code. I also need this.

[braca86]

how to send email to 2 or more reciptiens????
ive tried with

$to = "me@mydomain.com; me2@mydomain.com";
$subject = "File upload";
$body = "My file uploaded successfully... The link is: ";

and with

$to = "me@mydomain.com;
$to = "me2@mydomain.com";
$subject = "File upload";
$body = "My file uploaded successfully... The link is: ";

its not working... any help????

[therocket954]

Close. Try this:

PHP Code:

$to = "first@my-domain.com" . ", ";
$to .= "second@my-domain.com" . ", ";
$to .= "third@my-domain.com" . ", ";
$to .= "last@my-domain.com";