Ok i have this simple paging code that im currently testing and modify
this code will show 3 records per page in a table
this table have 4 columns
ID
FirstName
LastName
Age
The paging is working fine.....
the problem i'm having is in 2nd page the ID column is back to 1....and not 4
i want the id number in the id column to continue from previous page and to next page
page 1: ID: 1 2 3
page 2: ID: 4 5 6
and so on
here's my code
p/s: sorry for my english
PHP Code:
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Paging</title>
</head>
<body bgcolor="#ffffff" text="#000000" link="#0000ff" vlink="#800080" alink="#ff0000">
<?
require "connect.php"; // All database details will be included here
$page_name="paging.php"; // If you use this code with a different page ( or file ) name then change this
$start=$_GET['start'];
if(strlen($start) > 0 and !is_numeric($start)){
echo "Data Error";
exit;
}
$eu = ($start - 0);
$limit = 3; // No of records to be shown per page.
$this1 = $eu + $limit;
$back = $eu - $limit;
$next = $eu + $limit;
/////////////// WE have to find out the number of records in our table. We will use this to break the pages///////
$query2=" SELECT * FROM person ";
$result2=mysql_query($query2);
echo mysql_error();
$nume=mysql_num_rows($result2);
/////// The variable nume above will store the total number of records in the table////
/////////// Now let us print the table headers ////////////////
$bgcolor="#f1f1f1";
echo "<TABLE width=50% align=center cellpadding=0 cellspacing=0> <tr>";
echo "<td bgcolor='dfdfdf' > <font face='arial,verdana,helvetica' color='#000000' size='4'>ID</font></td>";
echo "<td bgcolor='dfdfdf' > <font face='arial,verdana,helvetica' color='#000000' size='4'>FirstName</font></td>";
echo "<td bgcolor='dfdfdf' > <font face='arial,verdana,helvetica' color='#000000' size='4'>LastName</font></td>";
echo "<td bgcolor='dfdfdf'> <font face='arial,verdana,helvetica' color='#000000' size='4'>Age</font></td></tr>";
////////////// Now let us start executing the query with variables $eu and $limit set at the top of the page///////////
$query=" SELECT * FROM person limit $eu, $limit ";
$result=mysql_query($query);
echo mysql_error();
$count=1;
//////////////// Now we will display the returned records in side the rows of the table/////////
while($noticia = mysql_fetch_array($result))
{
if($bgcolor=='#f1f1f1'){$bgcolor='#ffffff';}
else{$bgcolor='#f1f1f1';}
echo "<tr >";
echo "<td align=left bgcolor=$bgcolor id='title'> <font face='Verdana' size='2'>";
echo $count++;
echo "</font></td>";
echo "<td align=left bgcolor=$bgcolor id='title'> <font face='Verdana' size='2'>$noticia[firstname]</font></td>";
echo "<td align=left bgcolor=$bgcolor id='title'> <font face='Verdana' size='2'>$noticia[lastname]</font></td>";
echo "<td align=left bgcolor=$bgcolor id='title'> <font face='Verdana' size='2'>$noticia[age]</font></td>";
echo "</tr>";
}
echo "</table>";
////////////////////////////// End of displaying the table with records ////////////////////////
///////////////////////////////
if($nume > $limit ){ // Let us display bottom links if sufficient records are there for paging
/////////////// Start the bottom links with Prev and next link with page numbers /////////////////
echo "<table align = 'center' width='50%'><tr><td align='left' width='30%'>";
//// if our variable $back is equal to 0 or more then only we will display the link to move back ////////
if($back >=0) {
print "<a href='$page_name?start=$back'><font face='Verdana' size='2'>PREV</font></a>";
}
//////////////// Let us display the page links at center. We will not display the current page as a link ///////////
echo "</td><td align=center width='30%'>";
$i=0;
$l=1;
for($i=0;$i < $nume;$i=$i+$limit){
if($i <> $eu){
echo " <a href='$page_name?start=$i'><font face='Verdana' size='2'>$l</font></a> ";
}
else { echo "<font face='Verdana' size='4' color=red>$l</font>";} /// Current page is not displayed as link and given font color red
$l=$l+1;
}
echo "</td><td align='right' width='30%'>";
///////////// If we are not in the last page then Next link will be displayed. Here we check that /////
if($this1 < $nume) {
print "<a href='$page_name?start=$next'><font face='Verdana' size='2'>NEXT</font></a>";}
echo "</td></tr></table>";
}// end of if checking sufficient records are there to display bottom navigational link.
include "menu.php";
?>
</body>
</html>
Help with array in paging code
Linear Mode
