[sarahmx]

Hi its me again....

I'm trying to adapt the timediffrence function by JCBones here in a new program of mine..the code previously shows only hours and not days..right now i also want to show day if it after 24 hour..

like 1 day ago...2 days ago etc


right now my new code is working except it still show hours if if excedeed 24 hours....example

http://img695.imageshack.us/img695/2149/41633294.jpg

PHP Code:

function timeDifference($start,$end,$return='days') {
    $difference = max($end, $start) - min($end,$start);
    $time = NULL;
    //calculate time difference.
    switch($return) {
        case 'days':
             $days = floor($difference/86400);
                $difference = $difference % 86400;
                    $time['days'] = $days;
        case 'hours':
            $hours = floor($difference/3600);
                $difference = $difference % 3600;
                    $time['hours'] = $hours;
        case 'minutes':
            $minutes = floor($difference/60);
                $difference = $difference % 60;
                    $time['minutes'] = $minutes;
        case 'seconds':
            $seconds = $difference;
                $time['seconds'] = $seconds;
    }
    
    $output = array();
       if(is_array($time)) {
        $showSec = true;

if(isset($time['days']) && $time['days'] > 0) {
                        $output[] = $time['days'] . ' Days';
                        $showSec = false;
                    }


                    if(isset($time['hours']) && $time['hours'] > 0) {
                        $output[] = $time['hours'] . ' Hours';
                        $showSec = false;
                    }
                    
                    if(isset($time['minutes']) && $time['minutes'] > 0) {
                        $output[] = $time['minutes'] . ' Minutes';
                        $showSec = false;
                    }
                    
                    if(isset($time['seconds']) && $showSec == true) {
                        return $time['seconds'] . ' Seconds';
                    }
                
        
            return implode(', ',$output);
        }
}  


$now = time();
$hours = 24;
$time = ( intval( $hours ) > 0 ) ? time() - ( intval( $hours ) * 3600 ) : ( time() - 24*3600 ); 

PHP Code:

while($row = mysql_fetch_array($result))
{

$id=$row['id']; 
$mydate=$row['date'];
$showdate= $mydate ? formatTimestamp($mydate) : '';
$adate=$row[date];
$showdate2 = ' ' . timeDifference($adate,$now,'hours') . ' ago ';

echo '<tr class="', ++$int & 1 ? 'even' : 'odd', '">'; 
echo "<td>"; 
echo $countmesej++;
echo "</td>";
echo "<td>" . $row['mesej_title'] . "</td>";
echo "<td>test: $showdate | $showdate2  </td></tr>";

} 

this must be simple..but i can't figure this out...help a noob
p/s: sorry for my english

[Jcbones]

Try this:

PHP Code:

while($row = mysql_fetch_array($result))
{

$id=$row['id']; 
$mydate=$row['date'];
$showdate= $mydate ? formatTimestamp($mydate) : '';
$adate=$row[date];
$showdate2 = ' ' . timeDifference($adate,$now,'days') . ' ago ';

echo '<tr class="', ++$int & 1 ? 'even' : 'odd', '">'; 
echo "<td>"; 
echo $countmesej++;
echo "</td>";
echo "<td>" . $row['mesej_title'] . "</td>";
echo "<td>test: $showdate | $showdate2  </td></tr>";

} 

[sarahmx]

thanks Jcbones

i'm trying to do this 3 thing


1. 2 days ago instead of 2 Days, 1 Hours, 59 Minutes ago
2. 1 month ago if exceed 30/31 days
3. 1 year ago if exceed 1 year


any help ?

[sarahmx]

ok i found this...i want to do some like this..using the jcbones functions

PHP Code:

function _ago($tm,$rcs = 0) {
    $cur_tm = time(); $dif = $cur_tm-$tm;
    $pds = array('second','minute','hour','day','week','month','year','decade');
    $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);
    for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]);
   
    $no = floor($no); if($no <> 1) $pds[$v] .='s'; $x=sprintf("%d %s ",$no,$pds[$v]);
    if(($rcs == 1)&&($v >= 1)&&(($cur_tm-$_tm) > 0)) $x .= time_ago($_tm);
    return $x;
} 

second','minute','hour','day','week','month','year ','decade'

[Jcbones]

Try this:

PHP Code:

function timeDifference($start,$end,$return='decade') {
    $difference = max($end, $start) - min($end,$start);
    $time = NULL;
    //calculate time difference.
    switch($return) {
        case 'decade':
            $decade = floor($difference/315705600);
                $difference = $difference % 315705600;
                    $time['decade'] = $decade;
        case 'year':
            $year = floor($difference/31570560);
                $difference = $difference % 31570560;
                    $time['year'] = $year;
        case 'month':
            $month = floor($difference/2630880);
                $difference = $difference % 2630880;
                    $time['month'] = $month;
        case 'week':
            $week = floor($difference/604800);
                $difference = $difference % 604800;
                    $time['week'] = $week;
        case 'days':
             $days = floor($difference/86400);
                $difference = $difference % 86400;
                    $time['day'] = $days;
        case 'hours':
            $hours = floor($difference/3600);
                $difference = $difference % 3600;
                    $time['hour'] = $hours;
        case 'minutes':
            $minutes = floor($difference/60);
                $difference = $difference % 60;
                    $time['minute'] = $minutes;
        case 'seconds':
            $seconds = $difference;
                $time['second'] = $seconds;
    }   
    
       if(is_array($time)) {
            foreach($time as $key => $value) {
                if($value > 0) {
                    if($value > 1) {
                        $key = $key . 's';
                    }
                    return $value . ' ' . $key . ' ago.';
                }
            }
        }
    return false;
} 

PHP Code:

while($row = mysql_fetch_array($result))
{

$id=$row['id']; 
$mydate=$row['date'];
$showdate= $mydate ? formatTimestamp($mydate) : '';
$adate=$row[date];
$showdate2 = ' ' . timeDifference($adate,time());

echo '<tr class="', ++$int & 1 ? 'even' : 'odd', '">'; 
echo "<td>"; 
echo $countmesej++;
echo "</td>";
echo "<td>" . $row['mesej_title'] . "</td>";
echo "<td>test: $showdate | $showdate2  </td></tr>";

} 

[sarahmx]

thank you jcbones....