[Barnz1986]

Originally Posted by IKG

@ Mab: I tried what you suggested and got the "could not open" error listed. I also tried making it just "endicott/" but no luck...

Well the path to your directory must be wrong then.

[mab]

If you wanted to list the files in the current folder (where this php script is located/running from) you would use this -

PHP Code:

$dirname = "."; 

If your images folder (and the other sub folders within it) are located within the current folder, you would use this -

PHP Code:

$dirname = "./images/personal/endicott/"; 

This would also work -

PHP Code:

$dirname = "images/personal/endicott/"; 

If your images folder is located one level closer to the root, you would use this -

PHP Code:

$dirname = "../images/personal/endicott/"; 

[IKG]

Still doesn't work


Here's how my directory is set up: www.websitename.com/images/personal/endicott

I placed the .php file inside the endicott folder. I don't know what else to say.

[mab]

If the .php file is in the same folder that you want to display the files in, the first form will work - $dirname = ".";

What is it doing or not doing?

A function like the opendir($dirname) is pretty basic. If it is not working, there could be a permissions problem with the folder(s) or you have a problem with PHP functioning.

P.S. Use the "." form with a trailing slash - $dirname = "./"; Code that uses this later in the loop needs a trailing slash to form the link.

[wirenut60]

I posted this in another subject.

http://freepgs.com/bawbaw60/zip/html...lister-php.txt

Wirenut